File Upload to S3

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This is part 1 of uploading files to an applicant. In this documentation, you'll be uploading to your account's S3.

❗️
Secure data access is required
If your call returns with Secure data access is required, you'll need to contact [email protected] to enable your account to access secure data.

Part 2 is to link the file to the applicant. See next article on Link Applicant to Files in S3 to complete the upload to the applicant.

import json
import xml.etree.ElementTree
import mimetypes
import os
import requests

HOST="api.fountain.com"
API_KEY="K-9NB9DkxU7NdrB9eRBHCA"
APPLICANT="6d0d9434-2817-4b96-9ad4-e33a7f2a0adb"
FILENAME="dog.jpg"
UPLOAD_FILE=(FILENAME, open(FILENAME, 'rb'), mimetypes.guess_type(FILENAME)[0])
UPLOAD_KEY="test"

UPLOAD_URL="https://%s/v2/applicants/%s/secure_documents/upload" % (HOST, APPLICANT)
LINK_UPLOAD_URL="https://%s/v2/applicants/%s/secure_documents/link_upload" % (HOST, APPLICANT)

HEADERS = { 'X-ACCESS-TOKEN': API_KEY }

upload_response = requests.post(UPLOAD_URL, headers=HEADERS)
upload_response_json = json.loads(upload_response.text)
form_data = upload_response_json['form_data']
form_data['Content-type'] = ""

s3_upload_response = requests.post(upload_response_json['url'], data=form_data, files={'file': UPLOAD_FILE})

s3_upload_response_xml = xml.etree.ElementTree.fromstring(s3_upload_response.text)
s3_filename = s3_upload_response_xml.find("Key").text

finish_upload_data = {
    'key': UPLOAD_KEY,
    's3_key': s3_filename,
    'size': os.path.getsize(FILENAME),
}
finish_upload_response = requests.post(LINK_UPLOAD_URL, headers=HEADERS, json=finish_upload_data)
print(finish_upload_response)

Secure data access is required

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